Question

Current in primary coil of a mutual inductor is 2 A and is increasing at the rate of 3 A/s. If mutual inductance
is 4 H. find flux and emf in secondary coil.
(1) 12 Wb. 8 V
(2) 6 Wb, 12 V
(3) 12 Wb. 6 V
(4) 8 W, 12 V​

Answer 1

Answer:

4) 8 Wb , 12 V

Explanation:

We know that,

E= - M di/dt

Here M = 4 H , di/dt= 3 A and I = 2 A

So,

 E = 4(3) = 12 V

We know that

 Flux = M I

So,

  Flux = 4(2)= 8 Wb.

Hope this helps you.