Question

current of 12 amp is flowing through a resistance of 20 ohm for 5 min, calculate this amount of heat generated in calories (1 calories =4.2 joules)​

Answer 1

Explanation:

The heat generated is approximately equal to h=i^2*R*t

Here I= 5A

R=12 ohm

t= 60 sec

So h=25*12*60 =18000 joule =18 kJoule

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Answer 2

Answer:

205.71 k cal

Explanation:

Given :

Current i = 12 A

Resistance R = 20 Ω

Time t = 5 min = 5 × 60 sec = 300 sec

We're asked to find Heat :

We know :

H = i² R t

Putting values here we get :

H = 12² × 20 × 300 J

H = 144 × 6 × 10³ J

H = 864 k J

In term of cal :

H = 864 / 4.2 k cal :

H = 205.71 k cal

Hence we get required answer!