Current of 1A is drawn by a filament of an electric bulb . Number of electrons passing through a crosss section of the filament in 16 sec would be roughly
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Answered by
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heyy bro ur answer............
I = Q/t
Q = It
Also It = number of electrons × charge of electron
It = NE
Where N is the number of electrons
1 × 16/ 1.6 × 10^-19 it comes to 10^ 20.......
hope this will help u.............@kundan
I = Q/t
Q = It
Also It = number of electrons × charge of electron
It = NE
Where N is the number of electrons
1 × 16/ 1.6 × 10^-19 it comes to 10^ 20.......
hope this will help u.............@kundan
Answered by
1
hope this answer will help u
if hlp mark as brainliest
if hlp mark as brainliest
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