Current of 20amps flowing through a coil of 300 turns with flux 100 m-Weber. Find the reluctance of the coil.
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By using Poisson distribution,
P(x;μ)= x!/e^−μ μ^x
μ: The mean number of successes that occur in a specified region(parameter)
x: The actual number of successes that occur in a specified region.
P(x; μ): The Poisson probability that exactly x successes occur in a Poisson experiment, when the mean number of successes is μ
Poisson distribution with parameter 3 per hour. The probability that it receives 5 calls in 2 hours duration so, μ=3×2=6 and x=5
P(x;μ)= 5!/e^−6 3^5
Explanation:
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