Question

Current of 4.8 ampere is flowing through a
conductor. The number of electrons crossing
per second the cross-section of conductor will
be.
(1) 3 * 1019 (2) 3 x 1020
(3) 7.68 * 1020
(4) 7.68 * 1021​

Answer 1

Answer:

we have, I = ne/ t

since t = 1 s

therefore, 4.8 = (1.6 X 10^-19) X n

n = 3 X 10^19

so option (a) is your answer