current of 5A exists in 10 ohm resistor for 4 minutes find charge and no. of electrons that pass through any crpss section of resistor in this time
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Answered by
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Given: I= 5A, R=10ohm, t=4min=4×60=240 sec
I=Q/t
=》 Q= I×t = 5×240= 1200 electrons
Therefore, 1200 electrons pass through the cross section of wire in 4 mins.
I=Q/t
=》 Q= I×t = 5×240= 1200 electrons
Therefore, 1200 electrons pass through the cross section of wire in 4 mins.
Gautam1yo:
what about 10 ohm?
Answered by
0
Concept:
- Charge is the product of current and time
- Current is the charge per unit time
- Charge per electron
Given:
- Current I = 5A
- Time t = 4 mins = 4* 60 = 240 s
Find:
- The charge passing through the resistor
- The number of electrons passing through the resistor
Solution:
We know that charge is the product of current and time
Q = It
Q = 5 * 240 = 1200 C
We know that the charge each electron has is 1.6* 10^-19 C
The number of electrons can be found by dividing the total charge by the charge carried by each electron
n = 1200 C/1.6* 10^-19 C
n = 7.5 * 10^21
The charge is 1200 C and 7.5* 10^21 electrons pass through the cross-section of the resistor in the given time period.
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