current passing through 1ohm resistance is zero in the circuit show below then find emf E is
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The emf E in the circuit is 6 volts.
Explanation:
Using superposition theorem ,
when 6v source is considered and E is short circuited
Total resistance = 2 II 1 = 2/3 Ω
Hence current,
I = V/R = 6/2/3 = 9 A
Hence current in the 1Ω resistance due to 6v source
I₁ = 9 x 2/(2+1) = 6A
Similarly when E source is acting and 6v source is short circuited,
Then There will be no current flowing in the 2 Ω resistance as it will be short circuited.
Hence current in the 1Ω resistance
I₂ = V/R = E/1 = E amp
Since net current in the 1Ω resistor is 0, hence
I₁ - I₂ = 0
=> 6 - E = 0
=> E = 6v
Hence the emf E is 6 volts.
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