Physics, asked by saratchandrakum1104, 1 year ago

Current sensitivity of a moving coil galvanometer is 5 div/ma and its voltage sensitivity (angular deflection per unit voltage applied) is 20 div/v. The resistance of the galvanometer is

Answers

Answered by lidaralbany
50

Answer: The resistance of the galvanometer is 250 ohm.

Explanation:

Given that,

Current sensitivity = 5 div/ma

\dfrac{\theta}{i} = 5000 div/A

Voltage sensitivity = 20 div/v

\dfrac{\theta}{V} = 20 div/V

Now, the resistance of the galvanometer is

R= \dfrac{\dfrac{\theta}{i}}{\dfrac{\theta}{V}}

R = \dfrac{5000\ V}{20\ A}

R = 250\ \Omega                (\because \dfrac{V}{A} = \Omega)

Hence, the resistance of the galvanometer is 250 ohm.

Answered by prajapatikomal063
3

Answer:

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