Question

current through a metallic conductor' is tripled while it's resistance and the time are held constants . under these conditions the heat generated in the conductor will in increase by a factor 9​

Answer 1

Answer:

The heat produced in conducting wire is given by joules law as,

H=I

2

Rt

i ) The amount of heat produced in current conducting wire, is proportional to the square of the amount of current that is flowing through the circuit, when the electrical resistance of the wire and the time of current flow is constant.

ie H∝I

2

(when R, t are constant)

II) Heat generated due to the flow of current is proportional to the time of current flow, when the electrical resistance and amount of current flow is constant.

ie H∝t (when I,R are constant)

III) The amount of heat produced is proportional to the electrical resistance of the wire when the current in the circuit and the time of current flow is constant.

ie H∝R (when I, t are constant)

please make brain list answer please

Answer 2

The heat in the conductor increases by a factor of (b) 9.

Given:

Heat energy in the conductor.

To find:

New value of heat if current in the conductor is tripled keeping resistance and time constant.

Explanation:

• Heat is a form of energy produced in a conductor.

• It is caused by collision of electrons and protons since they flow in opposite direction when a potential difference is applied across a conductor.

• Examples where heating effect of electric current is observed is in an electric heater, electric iron etc. Or the most basic one is in, if we keep a table fan as well as a room TV running for a long period of time, it gets heated. This due to the same reason.

• In analytical terms, heat energy is directly proportional to the square of the current in the conductor, the resistance offered and the time for which the current flows through the conductor.

                                  $H = I^{2} R t$

• Since, it is also a form of energy, hence, its SI unit is Joule (J).

Solution:

According to the question,

Replacing I by 3I ; and

Substituting in the equation, we get, the new heat as

$H' = (3I)^{2}Rt$  $;$  $and$

$H' = 9I^{2}Rt$     ;   $or$

$H' = 9H$

Final answer:

Hence, the heat in the conductor increases by a factor of (b)9.

 

Although your question is incomplete, you might be referring to the question below.

Current through a metallic conductor is tripled while its resistance and the time are held constant. Under these conditions, the heat generated in the conductor will increase by a factor of :-

a) three

b) nine

c) six

d) twelve