Current through a wire is 0.5 amp when a potential difference of 2 volt
is applied across it. What will the current be if the potential difference is increased to 6 volt?
If the same wire is folded onto itself, then what current will flow through it with 6 volt
potential difference?
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1
Answer:
V= I R
I=V/R
i1/i2 = V1/V2
0.5/i2 =2/6
i2 = 0.5× 3 amp
=1.5 amp
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