Question

Curved Surface area of a right circular cylinder is 4.4 m2. If the radius of the base · of the culider is 0.7m, find its height​

Answer 1

$\large\underline{\bold{Given \:Question - }}$

• Curved Surface area of a right circular cylinder is 4.4 square meter. If the radius of the base of the cylinder is 0.7m, find its height.

$\large\underline{\bold{Solution-}}$

$\begin{gathered}\begin{gathered}\bf \:Given - \begin{cases} &\sf{CSA_{(cylinder)} = 4.4 \: {m}^{2} } \\ &\sf{radius_{(cylinder)} = 0.7 \: {m}^{2} } \end{cases}\end{gathered}\end{gathered}$

$\begin{gathered}\begin{gathered}\bf \:To\:find - \begin{cases} &\sf{height_{(cylinder)}}  \end{cases}\end{gathered}\end{gathered}$

$\begin{gathered}\Large{\bold{{\underline{Formula \: Used - }}}} \end{gathered}$

$\bull \: \: \: \boxed{ \bf{CSA_{(cylinder)} = 2\pi \: rh}}$

where,

• r is radius of cylinder

• h is height of cylinder

• CSA is Curved Surface Area of cylinder.

CALCULATION :-

Given that,

• Radius of cylinder, r = 0.7 m

• Curved Surface Area of cylinder, CSA = 4.4 m²

So,

We know that,

• Curved Surface Area of cylinder is given by

$\sf \: CSA_{(cylinder)} = 2\pi \: rh$

On substituting the values, we get

$\sf \: 4.4 = 2 \times \dfrac{22}{7} \times 0.7 \times h$

$\sf \: \dfrac{44}{10} = \dfrac{44}{7} \times \dfrac{7}{10} \times h$

$\therefore \: \: \boxed{ \bf \: h \: = \: 1 \: m}$

$\boxed{ \bf{ \: Hence, \: height_{(cylinder)} \: = \: 1 \: m \: }}$

Additional Information :-

$1. \: \: \boxed{ \bf{Volume_{(Cylinder)} = \pi \: {r}^{2}h }}$

$2. \: \: \boxed{ \bf{TSA_{(Cylinder)} = 2\pi \: r(h + r)}}$

where,

• r is radius of cylinder

• h is height of cylinder

• TSA is Total Surface Area of cylinder.