Question

Curved surface area of a right circular cylinder of height 35 cm is
440 cm² . Find the diameter of its base.




plz help​

Answer 1

Hello dear.

Surface area of cylinder =440cm2

⇒2πrh=440cm 2

⇒2× 22/7 ×3.5×h=440

⇒h= 154/ 440×7

=20cm

hope this helps u ☺️

Answer 2

Answer:-

$\green{\bigstar}$The diameter of the base is 4 cm.

• Given:-

Curved surface area of a right circular cylinder = 440 cm²

Height = 35 cm

• To Find:-

Diameter of its base = ?

• Solution:-

We know,

$\boxed{C.S.A \: of \: Cylinder = 2 \pi rh}$

here,

π = 22/7

h = 35 cm

r = ?

→ $440 = 2 \times \dfrac{22}{7} \times r \times 35$

→ $440 = \dfrac{44}{7} \times r \times 35$

→ $440 = 44 \times r \times 5$

→ $440 = 220 \times r$

→ $r = \dfrac{440}{220}$

→ r = 2 cm

Diameter = 2r

→ 2 × 2

→ 4 cm

Therefore, the diameter of the base is 4 cm.

$\red{\bigstar}$ Know More:-

$: \implies \displaystyle \tt Area \: of \: Cylinder \: = \pi r ^{2} \\ \\ : \implies \displaystyle \tt \: Circumference \: of \: Cylinder \: = 2 \pi r \\ \\ : \implies \displaystyle \tt \: T.S.A \: of \: Cylinder \: = 2 \pi r(h + r) \\ \\ : \implies \displaystyle \tt \: Volume \: of \: Cylinder \: = \pi r ^{2} h$