Question

Curved surface area of a triangle circular cylinder of hight 14cm is 88cm square. Find the diameter of the base of the cylinder​

Answer 1

Answer:

Step-by-step explanation:

ANSWER:-

• Given CSA as 88 cm^2
• Height as 14 cm
• We need to find the diameter

Concept:-

$\sf{CSA = 2 \times \pi \times r \times h}$

$\sf{Diameter = 2\times Radius}$

Let's Do!

$\sf{88 = 2 \times \dfrac{22}{7} \times 14 \times r}$

$\sf{\dfrac{88 \times 7}{22 \times 2} = 14 \times r}$

$\sf{\dfrac{88 \times 7}{22 \times 14 \times 2} = r}$

$\sf{\dfrac{8 \times 1}{2 \times 2 \times 2} = r}$

$\boxed{\sf{ r = 1}}$

Now, applying 2nd Formula

$\sf{Diameter = 2 \times 1}$

$\sf{Diameter = 2 \ cm}$

So, 2 cm is the answer.

Note:-

• Thoroughly revise the formulas.
• Also, keep a special note for the units provided.

Edit : CSA is 2× pi × r × h, 2 was mistakenly missed, and final answer corrected.

Answer 2

Answer:

$\huge \bf \: given$

• CSA = 88 cm²
• Height = 14 cm

$\huge \bf \: to \: find$

Diameter

$\huge \bf \: answer$

As we know that

CSA of cylinder = 2πrh

$88 = 2 \times \frac{22}{7} \times {r}^{2} \times 14$

$\frac{88 \times 7}{22} = 14 \times r$

$4 \times 7 = 14 \times r$

$28 = 14r$

$r \: = \frac{28}{14}$

$r = 2$

Diameter = Radius × 2

Diameter = 2 × 2

Diameter = 4 cm