Curved surface area of cylinder with base radius 1cm is 44cm.the height of cylinder is ___.
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Answered by
2
here
c.s.a.c=44
curved surface area of cylinder=pi×r(r+h)
44=22/7×1(1+h)
44×7/22=1+h
2×7=1+h
14=1+h
h=14-1
h=13cm
therefore the height of the cylinder is 13 cm
c.s.a.c=44
curved surface area of cylinder=pi×r(r+h)
44=22/7×1(1+h)
44×7/22=1+h
2×7=1+h
14=1+h
h=14-1
h=13cm
therefore the height of the cylinder is 13 cm
Anonymous:
wrong
Answered by
2
CURVED SURFACE AREA
OF CYLINDER
= 2πRH
HERE "R" IS RADIUS OF THE BASE OF THE CYLINDER AND "H" IS HEIGHT OF THE CYLINDER.
SO 2πRH=44CM^2
GIVEN RADIUS {R}=1CM
SO, TAKING π=22/7
2×(22/7)×1×H=44CM^2
(44/7)×H=44CM^2
H=(44/44)×7
H=7CM
SO HEIGHT IS 7CM OF THE CYLINDER.
THANKS FOR ASKING THE QUESTION.
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