Question

CuSO₄ (aq) + Fe (s) → FeSO₄ (aq) + Cu (s)
Divide the above equation into
1. Reduction half reaction
2. Oxidation half reaction

Answer 1

Reduction and oxidation half reactions are shown below-

•Half reactions are representative of type of reactions, where either only oxidation reaction is shown or only reduction reaction is shown.

•Oxidation half reactions shows oxidation of compounds.

•Reduction half reaction shows reduction of compounds.

•Oxidation is characterized by loss of electrons.

•In the reaction, the compounds and elements have oxidative and reductive state of +2 and -2.

•Oxidation of iron occurs, converting balanced octet into ionic form.

Fe --> Fe2+ + 2e

•Reduction is characterized by gain of electrons.

•The electrons lost by iron are taken up by copper, already present in ionic form.

•Hence, it completes its octet, giving stable solid form.

Cu2+ + 2e --> Cu

•Sulphate ions are transferred from copper ions to iron ions.