CuSo4 + Fe = Cu + FeSo4- write oxidation and reduction equations from the above reaction
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First of all, let us talk about a broader meaning of oxidation & reduction, rather than just in terms of oxygen and hydrogen.
Oxidation:
- Loss of electrons
- Gain of electronegative element
- Loss of electropositive element
Reduction:
- Gain of electrons
- Gain of electropositive element
- Loss of electronegative element
Now,the charge on all these ion are as;
Cu⁺²SO₄⁻² + Fe⁺² = Cu⁺² + Fe⁺²SO₄⁻²
- Cu is electropositive
- SO₄ is electronegative
- Fe is electropositive
As,
- Cu is losing a electronegative element so, CuSO₄ is getting reduced
- Fe is gaining a electronegative element, thus Fe is getting oxidized.
Conclusion: Oxidation - Fe & Reduction - CuSO₄
[Equation of both oxidation & reduction is already there,amn't getting the question properly.]
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