CuSO4 solution(250ml) was electrolysed using a platinum anode and a copper cathode.At constant current of 2mA was passed for 16 minutes.It was found that after electrolysis the absorbance of this solution was reduced to 50% of its original value.Then the concentration of copper sulphate in solution to begin with is
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CuSO4 solution(250ml) was electrolysed using a platinum anode and a copper cathode.At constant current of 2mA was passed for 16 minutes.It was found that after electrolysis the absorbance of this solution was reduced to 50% of its original value.Then the concentration of copper sulphate in solution to begin with is
(a)8×10−4(b)8×10−5(c)8×10−6(d)8×10−7
A)
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Total no of Faradays passed=2×10−3×16×6096500
⇒1.9×10−5
Moles of Cu+2 ions deposited =1.9×10−52
Since absorbance was reduced to 50% of its original value the initial moles of Cu+2 would be two times the moles of Cu+2 reduced.
∴ Initial moles of Cu+2=1.9×10−52×2
⇒1.9×10−5
The concentration of CuSO4 in solution =1.9896×10−5×4
⇒≈8×10−5mol/lit