* Cut HNO3 - Cu(NO3)₂ + NO + H₂O find redox reaction in Acetic method
with all the steps
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Answers
Answer:
Cu + HNO3 → Cu(NO3)2 + NO + H2O
Step 2. Separate the process into half reactions. A redox reaction is nothing but both oxidation and reduction reactions taking place simultaneously.
a) Assign oxidation numbers for each atom in the equation. Oxidation number (also called oxidation state) is a measure of the degree of oxidation of an atom in a substance (see: Rules for assigning oxidation numbers).
Cu0 + H+1N+5O-23 → Cu+2(N+5O-23)2 + N+2O-2 + H+12O-2
b) Identify and write out all redox couples in reaction. Identify which reactants are being oxidized (the oxidation number increases when it reacts) and which are being reduced (the oxidation number goes down). Write down the transfer of electrons. Carefully, insert coefficients, if necessary, to make the numbers of oxidized and reduced atoms equal on the two sides of each redox couples.
O:Cu0 → Cu+2(N+5O-23)2 + 2e-(Cu)
R:H+1N+5O-23 + 3e- → N+2O-2(N)
c) Combine these redox couples into two half-reactions: one for the oxidation, and one for the reduction (see: Divide the redox reaction into two half-reactions).
O:Cu0 → Cu+2(N+5O-23)2 + 2e-
R:H+1N+5O-23 + 3e- → N+2Second, verify that the sum of the charges on one side of the equation is equal to the sum of the charges on the other side. It doesn't matter what the charge is as long as it is the same on both sides.
3*0 + 8*0 = 3*0 + 2*0 + 4*0
0 = 0
Since the sum of individual atoms on the left side of the equation matches the sum of the same atoms on the right side, and since the charges on both sides are equal we can write a balanced equation.
3Cu + 8HNO3 → 3Cu(NO3)2 + 2NO + 4H2O