Question

Cx square +(c+d)x+d=0​

Answer 1

Answer:

Given equation is  $cx^2+(c+d)x+d=0$

       $cx^2+(c+d)x+d= 0$

       $cx^2+cx+dx+d= 0$

       $cx (x+1)+ d(x+1)=0$

       $(x+1)(cx+d)=0$

       $x+1=0 ;cx+d=0$

       $x=-1;cx=-d$

       $x=-1;x=-\frac{c}{d}$

Therefore the value of x= -1 and the root of x= -c/d

                 Hope it helps you^_^