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Answers
Answered by
3
The sample space has 6 possible outcomes-
S={1,2,3,4,5,6}.
Let all outcomes are equally likely(fair dice).
Hence Probability of any one outcome occurring= 1/6.
The event that we get that an even number on tossing the die can occur in 3 possible ways.
Let E denote this event.
E={2,4,6}
Now P(E)= 3×1/6=1/3
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