Question

CXERCISE 6.7 1. Find the highest number which divides 27 and 45 exactly. 2. Find the lowest number which when divided by 8 and 9 leaves 3 as remainder in each case.​

Answer 1

Answer:

1. The highest number which exactly divides 27 and 45 is the HCF(27, 45). Therefore, the required number is 9.

2. 75

Step-by-step explanation:

answer will be 75

solution

8×9 +3 = X

8×9=72

72+3=×

x = 75

so your answer is 75