Chemistry, asked by rameshmath122, 8 days ago

Cyanides with Sn + HCl gives(it is not stephen reduction)

Answers

Answered by marvaminuva

0

Correct option is

A

Stephen's reduction

In the Stephen's reduction alkyl cyanide is reduced to aldehyde by SnCl

2

/HCl.

R−C≡N+2H

SnCl

2

/HCl

alidinehydrochloride

RCH=NH.HCl

H

2

O

aldehyde

RCHO

+NH

4

Cl

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