Cyanides with Sn + HCl gives(it is not stephen reduction)
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Stephen's reduction
In the Stephen's reduction alkyl cyanide is reduced to aldehyde by SnCl
2
/HCl.
R−C≡N+2H
SnCl
2
/HCl
alidinehydrochloride
RCH=NH.HCl
H
2
O
aldehyde
RCHO
+NH
4
Cl
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