cyclic ABCD measure angle A + angle B =150 and angle B+ angle c=190 .find angle D
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A+B = 150 and B+C = 190
As ABCD is a cyclic quad, A+C =180
A+B+B+C+A+C = 520
2A + 2B + 2C = 520
2(A+B+C)= 520
A+B +C = 520/2
A+B+C =260
In a quad, A+B+C+D = 360
260 + D = 360
D = 360 - 260
D = 100
As ABCD is a cyclic quad, A+C =180
A+B+B+C+A+C = 520
2A + 2B + 2C = 520
2(A+B+C)= 520
A+B +C = 520/2
A+B+C =260
In a quad, A+B+C+D = 360
260 + D = 360
D = 360 - 260
D = 100
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