Question

cyclic quadrilateral abcd in whivh A=(2x-1)°,B=(y+5)°,C=(2y+15°),D=(4x-7°)

Answer 1

since there are two equations and two variables, you can solve them

Answer 2

Answer:

in cyclic quadrilateral the sum of opposite angle is 180

so:-

<A + <C = 180   => (put the value of <A and <C)

2x-1 + 2y+15 = 180 => 2x+2y=180-14=166

x + y=83   (eqn no 1)

<B + <D = 180  =>(again put the value of <B and <D)

y+5 + 4x-7 =180

4x+y= 180+2 = 182 (eqn no 2)

by elimination method:-

we get x= 33 and y=50

and then put the values of x and y in <A,<B,<C and <D

so we get <A=65

<B=55

<C=155

<D=125

HOPE IT IS HELPFUL

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