Question

cyclic rombas is a square prove​

Answer 1

$\huge\tt\pink{Answer}$

• ABCD is a  rhombus in circle...

∴ ∠A+∠C and ∠B+∠D ( Opposite  angle of rhombus is Equal)

∠A+∠C=180 degree   (Opposite angle of cyclic rhombus)

∴ ∠A+∠A=180 degree

⇒  ∠A=90 degree

• And ∠B+∠D=180  degree (Opposite angle of cyclic rhombus)

∴∠B+∠B=180 degree

⇒∠B=90 degree

∴∠A=∠B=∠C=∠D=90 degree

Then all angle of rhombus is right angle then this is a square

Answer 2

Step-by-step explanation:

ABCD is a rhombus in circle...

∴ ∠A+∠C and ∠B+∠D ( Opposite angle of rhombus is Equal)

∠A+∠C=180 degree (Opposite angle of cyclic rhombus)

∴ ∠A+∠A=180 degree

⇒ ∠A=90 degree

And ∠B+∠D=180 degree (Opposite angle of cyclic rhombus)

∴∠B+∠B=180 degree

⇒∠B=90 degree

∴∠A=∠B=∠C=∠D=90 degree

Then all angle of rhombus is right angle then this is a square