Question

Cyclist A and B cycled at an average speed of 15km/hr and 20km/hr respectively from the same starting point x on the same route.Cyclist B started his journey 6 min after Cyclist A started.(A part) What were the distances travelled by cyclists A and B 1 h after cyclist A started his journey from point x. (B part) Did cyclist B overtake cyclist A within the first hour of cyclist A's journey.

Answer 1

Answer:

Use speed s = distance(d)/time(t)

Since distance d is the same d = st

At 15 km/h, takes shorter time t

At 10 km/h, takes longer time (t + 2/3)

15(t) = (t + 2/3)10 => 15t = 10t + 20/3

5t = 20/3 => t = 20/15 = 4/3 h.

d = st = 15(4/3) or 10(2/3 + 4/3) = 20 km.

Explanation:

this answer is correct

Answer 2

Answer:

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