cyclist A moves at a speed x km/h from place in eastern direction.Cyclist B move (x+3) km/h from the same place towards northern direction.after 2 hours the distance between them is 30.find value of x
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Answered by
7
The value of x is =12
rushi17moon:
pls. eleborate
According to the question,
Cyclist A moves at a speed of x km/h then after 2 hours its distance will be (2x)
Similalry cyclist B will cover 2(x+3) distance after 2 hours.
Using Pythagoras
(2x)^2 + [2(x+3)]^2 = 30^2
Solving this quadratic equation you will get the answer.
Cyclist A moves at a speed of x km/h then after 2 hours its distance will be (2x)
Similalry cyclist B will cover 2(x+3) distance after 2 hours.
Using Pythagoras
(2x)^2 + [2(x+3)]^2 = 30^2
Solving this quadratic equation you will get the answer.
x= -12 and x= 9 ignore the negative term as speed can't be negative so the speed of cyclist A is 9km/hr and B is 12km/hr
Answered by
21
Answer:
Step-by-step explanation:
According to the question,
Cyclist A moves at a speed of x km/h then after 2 hours its distance will be (2x)
Similalry cyclist B will cover 2(x+3) distance after 2 hours.
Using Pythagoras
(2x)^2 + [2(x+3)]^2 = 30^2
Solving this quadratic equation you will get the answer.
x= -12 and x= 9 ignore the negative term as speed can't be negative so the speed of cyclist A is 9km/hr and B is 12km/hr
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