Question

cyclist moves in a circular track of radius 100 m. If the coefficient
of friction is 0.2 then the maximum speed with which the cyclist
can take a turn without leaning inwards is
[1]​

Answer 1

$\huge\underline\blue{\sf Answer:}$

$\large\red{\boxed{\sf Speed (v)=14\:m/s }}$

$\huge\underline\blue{\sf Solution:}$

$\large\underline\pink{\sf Given: }$

• Radius of cicular track (R) = 100m

• Coefficient of friction $\sf{(\mu)}$=0.2

$\large\underline\pink{\sf To\:Find: }$

• Maximum speed with which Cyclist turn without leaning inward (v)=?

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We know that ,

$\large{\boxed{\sf v=\mu Rg }}$

On putting value :-

$\large\implies{\sf v=\sqrt{0.2×100×10}}$

$\large\implies{\sf v=10\sqrt{2}}$

Value of $\sf{\sqrt{2}=1.4}$

$\large\implies{\sf v=10×1.4 }$

$\large\implies{\sf v=14\:m/s }$

$\large\red{\boxed{\sf Speed (v)=14\:m/s }}$

Hence ,

Maximum speed with which the cyclist can turn without leaning inwards is

14m/s

Answer 2

$\huge{\mathfrak{\underline{\orange{Answer:-}}}}$

$\large\pink{\boxed{\tt Velocity=14m/s}}$

$\large\bf{\bold{\underline{\underline{Given:-}}}}$

$\star\sf\ <strong>Radius</strong> \:of \:track(R)=100m \\ \\ \star\sf\ Coefficient of friction (μ)=0.2$

$\large\bf{\bold{\underline{\underline{To\: find:-}}}}$

$\star\sf\ Maximum speed(v)=?$

$\large\bf{\bold{\underline{\underline{Solution:-}}}}$

Formula used ;

$\large\red{\boxed{\bf v= μRg}}$

Now; let us constitute given values

$\large\sf\implies\ v= \sqrt {0.2 \times\ 100 \times\ 10}$

$\large\sf\implies\ v=10\sqrt 2$

$\large\red{\boxed{\sf\sqrt 2 = 1.4 }}$

$\large\sf\implies\ v = 10 \times\ 1.4$

$\large\sf\implies\ 14m/s$