Question

cyclist moving with speed 10m/sec for 8 sec. with constant acceleration15m/sec2.Find distance travelled by cyclist?​

Answer 1

Answer:

The answer is easy!

Explanation:

acceleration(a)= 15 m$s^{-1}$

time(t)=8s

initial velocity is given(u)=10m/s

distance(s)=?

we know that:

s=u*t+ $\frac{1}{2}$ * a*$t^{2}$

s=10*8+$\frac{1}{2}$*15*64

s=560m

The distance travelled is 560m

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Answer 2

Explanation:

Here initial velocity u = 10m/sec

acceleration a = 15m/sec²

time t = 8sec

let, distance traveled by cyclists be s metre

then applying the equation s = ut+½at² we obtain

s = 10×8+½×15×8²

s = 80+480

s = 560 m

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