Question

cyclist of mass 30 kg exert a force of 250 Newton to move a cycle acceleration is 4 metre per second square find force of friction between the roads and tyre will be​

Answer 1

$\huge\underline{\underline{\bf \orange{Question-}}}$

Cyclist of mass 30 kg exert a force of 250 Newton to move a cycle acceleration is 4 metre per second square find force of friction between the roads and tyre will be

$\huge\underline{\underline{\bf \orange{Solution-}}}$

$\large\underline{\underline{\sf Given:}}$

• Force (F) = 250N
• Mass (m) = 30kg
• Acceleration (a) = 4m/s²

$\large\underline{\underline{\sf To\:Find:}}$

• Force of friction (f).

✪${\boxed{\bf \blue{Force(F)-force\:of\: friction (f)=ma} }}$

$\implies{\sf 250-f=30×4 }$

$\implies{\sf 250-f=120 }$

$\implies{\sf f = 250-120 }$

$\implies{\bf \red{Force\:of\: friction (f) = 130N }}$

$\huge\underline{\underline{\bf \orange{Answer-}}}$

Force of friction is ${\bf \red{130N}}$.

Answer 2

$\huge\mathfrak\purple{Given :-}$

Force (F) = 250N

Mass (m) = 30kg

Acceleration (a) = 4m/s²

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$\huge\mathfrak\purple{To\: Find }$

Force of friction (f)

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$\huge\mathfrak\purple{Solution :- }$

${\boxed{\bf \blue{Force(F)-force\:of\: friction (f)=ma} }}$

$\implies{\sf 250-f=30×4}$

$\implies{\sf 250-f=120 }$

$\implies{\sf f = 250-120 }$

$\implies{\bf \red{Force\:of\: friction (f) = 130 N}}$

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$\huge\mathfrak\purple{Answer:- }$

Force of friction is 130 N