Question

Cyclist starts from rest and acceleration at the rate of 2 metre per second square what will be his velocity after 5 seconds.
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Answer with explanation~
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Answer 1

Answer:

Velocity of bus V

b

=0 , Velocity of cyclist V

c

=20m/s,

Acceleration of bus a

b

=2m/s

2

Acceleration of cyclist a

c

=0

Relative velocity V

cb

=V

c

−V

b

=20m/s

Relative acceleration a

cb

=a

c

−a

b

=−2m/s

2

Relative separation =96m

Using s=ut+

2

1

at

2

⇒96=20t−

2

1

2t

2

⇒t

2

−20t+96=0

Solving the equation , we get t=8s and t=12s

Hence, after 8s, cyclist will overtake the bus.

Explanation:

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Answer 2

Answer:

10 m/s

Explanation:

$\underline{\bigstar\:\textsf{Given:}}$

• Acceleration (a) = 2 m/s²
• Initial velocity (u) = 0 m/s
• Time (t) = 5 s

$\underline{\bigstar\:\textsf{To\:find:}}$

• Final velocity (v) = ?

$\underline{\bigstar\:\textsf{Solution:}}$

Analysis:

There is a cyclist starts from rest accelerates with an acceleration of 2 m/s². Now we have to calculate final velocity of cyclist after 5 seconds.

Let's find now !

If we remember, we have Newton's first law of motion i.e, $\blue{\sf{v\:=\:u\:+\:at}}$

[just put all the given values]

$\longrightarrow$ v = 0 + 2 × 5

$\longrightarrow$ v = 10 m/s

$\sf{\underline{\boxed{\large{\mathsf{\therefore \:Velocity\:is\:10\:m/s}}}}}$

__________________________________

$\underline{\bigstar\:\textsf{Verification:}}$

[put all the values again in the formula]

$\implies$ 10 = 0 + 2 × 5

$\implies$ 10 = 0 + 20

$\implies$ 10 = 10

LHS = RHS. Hence, verified ✔.

Hope it helped you dear...