cyclists are travelling around a track at 14m/s. when they leave it they accelerate from 14m/s to 18m/s at a steady rate, which takes them 3 seconds. what distance did they travel in this time?
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Explanation:
initial velocity = 14m/s
acceleration = final velocity - initial velocity
= 18m/s - 14m/s
= 4m/s²
time = 3 second
distance = (?)
s = ut + 1/2 at²
= 14m/s (3 ) + 1/2 (4m/s × 3² )
= 14 m/s ×3 + 2 ×9
= 14×3+ 18
= 60 m distance
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