Question

Cycloalkane formed when 1, 4-dibromopentane is heated with sodium is:

Answer 1

Cycloalkane formed when 1,4-dibromopehtane is heated with Sodium is (A) Methyl cyclobutane (B) Cyclopentane

Answer 2

Cycloalkane formed when 1, 4-dibromopentane is heated with sodium is Methyl cyclobutane.

Explanation:

• The formula of 1,4-dibromopentane is  $Br-CH_2-CH_2-CH_2-C(Br)$ -$CH_3$.

• 1,4-dibromopentane contains 5 carbon atoms and two bromine atom at 1st and 4th position.

• When the compound 1,4-dibromopentane is heated with 'sodium' in the  leads to the formation of methyl cyclobutance.

• In methyl cyclobutane 4 carbon atoms are forming the circular ring and a methyl group is attached to one of the Corner carbon atoms of the ring structure.

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