Question

Cyclohexanol is dehydrated to cyclohexane on heating with conc. h2so4. if the yield of this reaction is 75% how much cyclohexene will be obtained from 100 g of cyclohexanol?

Answer 1

C6H13OH→C6H12C6H13OH→C6H12

Mole weight of C6H13OH=102C6H13OH=102

Mole weight of C6H12=84C6H12=84

102g102g cyclohexanol =84gC6H1284gC6H12

∴∴ 100g cyclohexanol =84×100g10284×100g102C6H12C6H12

Also %% yield is 75%

Weight of C6H12=84×100×75100×102C6H12=84×100×75100×102

Answer 2

Answer:

61.5 grams of cyclohexene will be obtained from 100 g of cyclohexanol.

Explanation:

1 Cyclohexanol + sulfuric acid → 1 Cyclohexene

Moles of cyclohexanol =$\frac{100 g}{100 g/mol}=1 mol$

According to reaction 1 mole of cyclohexanol is getting dehydrated 1 mole of cyclohexene .

Mass of 1 mol of cyclohexene = 1 mol × 82 g/mol =82 g

$\%\text{ yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100$

% yield of reaction = 75 %

Theoretical yield of D = 82 g

Putting values in above equation, we get:

$75\%=\frac{\text{Experimental yield}}{82 g}\times 100\\\\\text{Experimental yield}=61.5 g$

61.5 grams of cyclohexene will be obtained from 100 g of cyclohexanol.