cylinder 25 cm long and 8 cm in cross – section, is filled with water. Calculate i) The pressure and ii) The thrust exerted by water on the bottom of the
cylinder.
Answers
Given info : A cylinder 25cm long and 8cm² in cross-section is filled with water.
To find :
- pressure
- thrust exerted by water on the bottom of the cylinder.
solution : pressure at the bottom of cylinder = ρgh
where ρ = density of water = 10³ kg/m³
g = acceleration due to gravity = 9.8 m/s²
h = length of cylinder = 25cm = 0.25 m
now, pressure = 10³ × 9.8 × 0.25
= 2.45 × 10³ N/m²
thrust exerted by water on the bottom of the cylinder = pressure × base area
= 2.45 × 10³ N/m² × 8 cm²
= 2.45 × 10³ N/m² × 8 × 10¯⁴ m²
= 1.96 N
Therefore thrust exerted by water on the bottom of the cylinder is 1.96 N.
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