Question

Cylindrical tank has a capacity of 6160 cubic centimetre find the depth of the radius is 14 M calculate the cost of the painting at curved outer surface at a rate of 3 per square metre

Answer 1

Given that : The radius of base of cylinder = 14 m

And also given that :

Volume of cylinder = 6160 m³

As we know that : Volume of cylinder

$\pi {r}^{2} h$

Now, according to the question :

$\frac{22}{7} \times 14 \times 14 \times h = 6160 \\ \\ = > h = 10 \: m$

So, the height will be 10 m

Now, Curved surface Area of cylinder

$2 \times \frac{22}{7} \times 14 \times 10 \\ \\ = > 880 \: {m}^{2}$

Also given that : cost of per m² = Rs. 3

Then Cost of 880 m² = 3×880 = Rs. 2640

Answer 2

Volume of cylindrical tank=
$6160 {cm}^{3}$
Rdius of the cylindrical tank=14M
Height=?
Volume of cylinder= pie r(square) h
$6160 {cm}^{3} = \frac{22}{7} \times {14}^{2} \times h$
$h = 6160 \times \frac{7}{22} \times \frac{1}{196}$
dividing 6160 with 22
$h = 280 \times \frac{7}{1} \times \frac{1}{196}$
multiplying 280 with 7
$h = 1960 \times \frac{1}{196}$
dividing 1960 with 196
$h = 10 \times 1$
$h = 10m$
Curved Surface Area=
$2\pi \: rh$
$2 \times \frac{22}{7} \times 14 \times 10$
$44 \times 2 \times 10$
$88 \times 10$
$880 {m}^{2}$
Cost of painting per square metre =$3
Cost of painting the 880 meter square =
$880 {m}^{2} \times 3$
$2640$
2640 rupess