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9: ABCD is a rhombus. If angle ADB = 50°, find the
angles of the rhombus.
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Answer:
ABCD is a rhombus
AB = BC = CD = AD
angle ABC = angle ADC
angle BAD = angle BCD
AB || CD and AD || BC
angle DAC = angle BCA = 50°
50 + n + y + 50 + n + y = 360°
2n + 2y = 260°
n + y = 130°
Diagonal bisect the angles
n = 50°, y = 130-50
=80°
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