Question

D
1. In the figure ray CD stands on AB at C. If
BCD = (5x + 30) and
ACD= (2x + 10)° find the
Value of BCD and ACD
(5x+30°
(2x+10) find the value of angle BCD and angle ACD​

Answer 1

Step-by-step explanation:

5x+30+2x+10=180 linear pair

7x+40=180

7x=140

X=20

angle bcd=5×20+30=130

ACD=2×20+10=50