Question

(D) 1
Three numbers are in the ratio 4:5:6 and thei
average is 30. The largest number is:
(A) 28
(B) 32
(C) 36
(D) 42
"Fidel Castro" was the leader of​

Answer 1

Answer:

☆ Given ☆

$\textsf{Total number given = 3}$

$\textsf{Three numbers are in ratio = 4:5:6}$

$\textsf{Average of the numbers = 30}$

☆ To find ☆

$\textsf{The largest number}$

☆ Taken ☆

Use the average formula to find the largest number:

Let the ratio be x

$\Large{\underline{\boxed{L=\frac{R}{N}=30}}}$

Where,

L = Largest number

R = Sum of all the ratio

N = Total No. of numbers given

☆ Concept ☆

When you find the the value of 1 of the ratio . Then multiply it with the biggest ratio to find the largest number .

☆ Solution ☆

$\:\:\:\:\:\:\:\:\:\:\:\:\implies{L=>\frac{4x+5x+6x}{3}=30}$

$\:\:\:\:\:\:\:\:\:\:\:\:\implies{L=>\frac{15x}{3}=30}$

$\:\:\:\:\:\:\:\:\:\:\:\:\implies{L=>15x=90}$

$\:\:\:\:\:\:\:\:\:\:\:\:\implies{L=>x=90/15}$

$\:\:\:\:\:\:\:\:\:\:\:\:\implies{L=>x=6}$

So , the value of 1 or x is 6 .

Now , find the largest number .

$\:\:\:\:\:\:\:\:\:\:\:\:\implies{L=>6×6}$

$\:\:\:\:\:\:\:\:\:\:\:\:\implies{L=>36}$

☆ Answer ☆

So , the largest number is 36 .

☆ Extra information ☆

Rest two numbers are :

1) 4 × 6 = 24

2) 5 × 6 = 30

And the each numbers are 36 , 30 and 24 .

Answer 2

Let the no.’s be- 4x, 5x and 6x.
According to the question,
4x+ 5x+ 6x /3=30
15x = 90
x= 90/15
Therefore, x= 6.
The no.’s are= 4(6)= 24
= 5(6)= 30
= 6(6)= 36
Hence, correct option is (C) 36 as it is the largest among the rest of the no.’s




Hope you are satisfied with this. :)