Question

d) 1 unit
A sample of CaCO3 contains 3.01 x 1023 ions of Ca*2 and CO 2 The mass of the sample is
8.
a) 200g
b) 50 g
c) 100 g
d) 5 g
Ans plz​

Answer 1

Answer:

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Answer 2

Answer:We know that CaCO  

3

​  

 contains 1 mole of both Ca  

2+

 and CO  

3

2−

​  

 ions that is, 6.02×10  

23

 ions of both the ions.

Now, since the number of ions in the question is given to be 3.01×10  

23

 which is half of 6.02×10  

23

, hence, the number of moles will also get halved.

Since we know that moles=  

Molecular mass

Given mass

​  

 

Therefore,  

2

1

​  

=  

100

Required mass of CaCO  

3

​  

 

​  

 

Required mass of CaCO  

3

​  

=50g

Hence, option (b) is correct.

Step-by-step explanation: