Question

(d) 10
(a) 1
(b) 10
(iv) The logarithm of any number to itself as base is
(a) 1
(b) 0
(c)-1
where ez 2.718
og
di
$y = log10$
​

Answer 1

Step-by-step explanation:

More generally, exponentiation allows any positive real number as base to be raised to any real power, always producing a positive result, so logb(x) for any two positive real numbers b and x, where b is not equal to 1, is always a unique real number y. More explicitly, the defining relation between exponentiation and logarithm is:

{\displaystyle \log _{b}(x)=y\ }{\displaystyle \log _{b}(x)=y\ } exactly if {\displaystyle \ b^{y}=x\ }{\displaystyle \ b^{y}=x\ } and {\displaystyle \ x>0}{\displaystyle \ x>0} and {\displaystyle \ b>0}{\displaystyle \ b>0} and {\displaystyle \ b\neq 1}{\displaystyle \ b\neq 1}.

For example, log2 64 = 6, as 26 = 64.

Answer 2

Answer:

a)1

b)0

thank you......