Question

D С ) 13 3х о x+y 5+ 2х А B




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Answer 1

Step-by-step explanation:

To find the least 5 digit number which is exactly divisible by 20, 25 and 30, we

have to first find the LCM of 20, 25 and 30

20 = 225

25 = 55

30 = 235

LCM = 22355 = 300

So, LCM of 20, 25 and 30 is 300. But we want the least 5 digit number, which is exactly divisible by 20, 25 and 30.

Least 5 digit number = 10000.

10000 = 33300 + 100

Next higher quotient is 34.

So, the required number = 34300

= 10,200

Hence, the required number is 10,200, which is exactly divisible by 20, 25 and 30.