Math, asked by 1ds18bt052shivani, 1 month ago

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19
at "
18
( ae
a-
2
0

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Answered by beuehyg6gy
0

Answer:

Length of AB = \sqrt{(1-1)^2 + (6-2)^2} = \sqrt{0^2 + 4^2} = \sqrt{0 + 16} = \sqrt{16} = 4(1−1)2+(6−2)2=02+42=0+16=16=4

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