Question

(D^2+6D+9)y=e^3x/x^3​

Answer 1

Step-by-step explanation:

The A.E is m2 + 6m + 9 = 0

Answer 2

Answer:

$( {d}^{2} + 6d + 9)y = {e}^{ \frac{3x}{ {x}^{3} } } \\ \\ = > {d}^{2} y + 6dy + 9y = {e}^{3 {x}^{1 - 3} } \\ \\ = > {d}^{2} y + 6dy + 9y = {e}^{3 {x}^{ - 2} }$