d) 2
9.
Magnitude of magnetic field intensity at a point around a current carrying conductor is B. If the
strength of current in the conductor becomes double, then the magnitude of magnetic field intensity at
the point around the conductor is:
B.
B
b) B
2
c)
d) 2B
4
A conductor of length 50 cm, carrying current of 0.1 A, when placed perpendicular to direction of
magnetic field 0.2 T experience force :
a) 1.0N
b) 0.1 N
c)0.01N
d) 0.01 N.
a)
10.
Answers
Answered by
0
Answer:
x
2
×x
6
=x
2+6
=x
8
{x}^{5} \div {x}^{3} = {x}^{5 - 3} = {x}^{2}x
5
÷x
3
=x
5−3
=x
2
{( {x}^{2} })^{4} = {x}^{8}(x
2
)
4
=x
8
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