((D+2)(D + 4))y = ex + sin 2x Particular integral?
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D2+4)y=sin2x
complementary function (C.F.) is obtained by putting D2+4=0⟹D=±2i
∴C.F.=C1cos2x+C2sin2x
Now, particular integral (P.I.) is found out as follows
P.I.=sin2xD2+4
=1−cos2x2D2+4
=12(1−cos2xD2+4)
=12(1D2+4−cos2xD2+4)
=12(e0⋅xD2+4−xcos2x2D)
=12(102+4−x21D(cos2x))
=12(14−x2sin2x2)
=18−xsin2x8
∴y=CF+PI
y=C1cos2x+C2sin2x+18−xsin2x8
y=C1cos2x+C2sin2x+1−xsin2x8
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