Question

D) -20 V
Q.42 A tin nucleus has charge + 50e. If the proton is at a distance 10-12 m from the nucleus,
then the potential V at this position is (charge on the proton = 1.6x10-1°C]
A) 14.4x104 volt
e) 7.2x104 volt
B) 7.2 108 volt
D) 14.4x108 volt​

Answer 1

Charge on the nucleus

Q = 50 eV

=50×1.6×10

−19

=80×10

−19

Distance of proton from nucleus

r=10

−12

m

Potential of this position is given by

V= 1/4πl0.Q/r

9×109×80×1019/10-12

7.2×104V