Math, asked by bariabharatkumar914, 4 months ago

d) 200 cm
o as directed.
1) Complete the table.
No Name of toys Quantity
Price per
item Total
1 Tambourine
2
200
2
Whistle
5
50
3 Mobile phone
4
125
Total rupees
2) Answer the questions based on the table.
Name of the ride Price
Time
Toy train
20
10 minutes
Dancing car
30
10 minutes
Boating
25
10 minutes
1. You have Rs. 200. What is the maximum number of tickets you can buy for
dancing car?
2. If you sit once in each ride what is the total cost of the ride?
3. How many times can you go for boating in Rs 75?
as directed​

Answers

Answered by RvChaudharY50
3

Given :-

Name of the ride Price Time

Toy train 20 10 minutes

Dancing car. 30 10 minutes

Boating 25 10 minutes

You have Rs. 200. What is the maximum number of tickets you can buy for a dancing car ?

If you sit once in each ride what is the total cost of the ride ?

How many times can you go for boating in Rs.75 ?

Solution :-

→ Price of dancing car = Rs.30

so,

→ In Rs.200 , total number of tickets can buy = (200/30) = 20/3 = 6.66 ≈ 6 tickets. (Ans.1)

now,

→ Total cost of all rides = Toy train price + dancing car price + boating price = 20 + 30 + 25 = Rs.75 (Ans.2)

also,

→ cost of Boating = Rs.25

then,

→ Total times we can go for boating in Rs.75 = 75 / 25 = 3 times. (Ans.3)

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