Question

d^2y/dx^2-5dy/dx+6y=e^4x

Answer 1

\left[d _{1}\right] = \left[ \frac{\left( -1\,i \right) \,\sqrt{\left( \left( -5\right) \,dx\,dy-dx^{2}\,e^{4}\,x+6\,dx^{2}\,y\right) }}{\sqrt{y}}\right][d​1​​]=[​√​y​​​​​(−1i)√​((−5)dxdy−dx​2​​e​4​​x+6dx​2​​y)​​​​​] totally answer