Question

d^2y/dx^2+a^2y=cosecax apply the method of variation of parameter​

Answer 1

Answer:

The given equation in its symbolic form is (D2 + a2)y = cosecax  

Thus, the auxiliary equation becomes D2 + a2 = 0  i.e. D = ±ia If a = 1,

then differential equation reduces to

d2y/dx2 + y =  secx

and the corresponding solution becomes

y = (c1cosx + c2sinx) + sinx(logsinx) – x cosx